Question

find the value of x in the equation 2 (x+2)+5(x+5)=4(x-8)+2(x-2)​

Answer 1

Answer:

–65

Step-by-step explanation:

Here , we have to solve for x. We have been given an equation that is,

$\longrightarrow \sf{\quad {2(x + 2) + 5(x + 5) = 4(x - 8) + 2(x - 2) }}$

Here, we'll be using the transposition method to solve this particular question. Transposing method is the method used to solve a linear equation having variables and constants. In this method, we transpose the values from R.H.S to L.H.S and vice-versa and changes its sign while transposing to find the value of the unknown value.

Firstly, let's use the distributive property to perform the multiplication of a polynomial with a binomial.

$\\ \longrightarrow \sf {2(x) + 2(2) + 5(x) + 5(5) = 4(x) + 4( - 8) + 2(x) +2( - 2) }$

Now, performing multiplication.

$\\ \longrightarrow \sf {2x+ 4+ 5x+ 25 = 4x -32 + 2x - 4 }$

Grouping the like term in L.H.S and R.H.S.

$\\ \longrightarrow \sf {2x+5x+ 25 + 4 = 4x +2x -32 - 4 }$

Performing addition and subtraction of terms in L.H.S and R.H.S.

$\\ \longrightarrow \sf {7x+ 29 = 6x -36 }$

Now, transposing all the like terms. Their sign will get changed.

$\\ \longrightarrow \sf {7x-6x = -36 -29 }$

Performing subtraction in both sides.

$\\ \longrightarrow \underline{ \boxed{ \textbf{\textsf{x = -65}}}}$

Therefore, the value of x is –65.

Answer 2

Step-by-step explanation:

Please refer to the attachment .

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