Question

Find the value of x in the equation sin2x = sin 45° cos 45°+ sin 30°
→Note:- Please don't give any unnecessary answer as well as wrong answer I request to all... and by the way it's a question of class 10's sample papers.​​​

Answer 1

Answer:

x=45

Step-by-step explanation:

sin2x= sin45cos45+sin30

sin2x= 1/√2×1/√2+1/2

sin2x=1/2+1/2

sin2x=1

sin2x=sin90

2x=90

x=45

Answer 2

The value of x = 45° in the equation sin2x = sin 45° cos 45° + sin 30°

Given : sin2x = sin 45° cos 45° + sin 30°

To find : The value of x

Solution :

Step 1 of 2 :

Write down the given equation

The given equation is

sin2x = sin 45° cos 45° + sin 30°

Step 2 of 2 :

Find the value of x

We find the value of x as below

sin2x = sin 45° cos 45° + sin 30°

$\displaystyle \sf{ \implies sin \: 2x = \bigg( \frac{1}{ \sqrt{2} } \times \frac{1}{ \sqrt{2} } \bigg) + \frac{1}{2} }$

$\displaystyle \sf{ \implies sin \: 2x = \frac{1}{2} + \frac{1}{2} }$

$\displaystyle \sf{ \implies sin \: 2x = 1 }$

$\displaystyle \sf{ \implies sin \: 2x = sin \: {90}^{ \circ} }$

$\displaystyle \sf{ \implies \: 2x = \: {90}^{ \circ} }$

$\displaystyle \sf{ \implies \: x = \: {45}^{ \circ} }$

The value of x = 45°

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