Question

find the value of x in the figure given above​

Answer 1

Answer:

30°

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Answer 2

Answer:

I am assuming that ABCD is a square and BEC is an equilateral triangle.

EC=BC (sides of an equilateral Δ are equal)

CD=BC(sides of square)

⇒EC=CD

∠CED=∠CDE(angles opposite to equal sides are equal) [1]

∠ECB+∠BCD = ∠ECD

60°+90° = ∠ECD (angles of square and equilateral Δ)

∠ECD = 150° [2]

Consider ΔECD,

∠ECD+∠CED+∠CDE = 180°(angle sum theory of a triangle)

150°+2∠CED = 180° (by [1] and [2] )

2∠CED = 30°

∠CED = 15° [3]

∠BEC = 60° (angle of an equilateral Δ)

∠BEC = ∠BED+∠CED

60° = ∠x + 15° (by [3] )

∠x = 60°-15° = 45°