Question

Find the value of x in the figure given above where BC = 6cm and AB= 10 cm.​

Answer 1

Answer:

Step-by-step explanation:

AB is the diameter.

OB is the radius.

Therefore, OB=AB/2

OB=10/2

OB=5

BC is a chord.

OM is the line joining the centre of the circle to the chord.

Angle OMB= 90°

Perpendicular drawn from the centre of the circle to its chord bisects the chord.

Therefore, M is the midpoint of BC.

Therefore, BM=BC/2

BM=6/2

BM=3

In ΔOMB,

Angle OMB=90°

Therefore, by Pythagoras theorem,

OBsquare =OM square + BM square

(5)square= (OM)square + (3)square

25= (OM)square + 9

(OM)square= 25-9

= 16

OM=√16

OM=4

X=OM

X=4