Question

find the value of x in the figure given below .​

Answer 1

Step-by-step explanation:

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Answer 2

$\sf \Large Solution!!$

$\sf \angle AOC+\angle BOC=180^{\circ} \quad (Linear\:pair)$

$\sf 3x^{\circ} +7x^{\circ} =180^{\circ}$

$\sf 10x^{\circ} =180^{\circ}$

$\sf x^{\circ} =\frac{18\cancel 0}{1\cancel 0}$

$\sf x^{\circ} =18^{\circ}$

$\sf \large So,$

$\sf \to \angle AOC=3x^{\circ}=54^{\circ}$

$\sf \to \angle BOC=7x^{\circ}=126^{\circ}$

$\sf \large Verification:$

$\sf \angle AOC+\angle BOC=180^{\circ}$

$\sf 54^{\circ}+126^{\circ}=180^{\circ}$

$\sf \cancel{180}^{\circ}=\cancel{180}^{\circ}$

Verified!!

Thanks for asking!! :)