Math, asked by toobamahar61, 6 months ago

Find the value of x in the following:
(11) log32 x
1
2

Answers

Answered by pragati3652

0

Step-by-step explanation:

log32+logx

5log2+logx

.3010×5+logx=0

logx=-.1550

antilog (-.1550)=

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