Question

find the value of x in the following ​

Answer 1

We know that :-

Vertically opposite angles are equal.

so 3x + 2= 62

hence 3x= 60

x = 20

Answer 2

$\huge\bold{\gray{\sf{Answer:}}}$

$\bold{Explanation:}$

In the figure above It is given $\angle DOA=(3x+2)^{\circ}$ and $\angle DOE =62^{\circ}$

A Property of triangle used here :-

Vertically Opposite Angle

Vertically opposite angles are the angles which is formed when any two lines intersects each other ,then the angles which ia formed due to intersection on both the sides are the pair of vertically opposite angles.

Now ,come to the Question :-

$\angle BOA=\angle DOE=62^{\circ}$

Reason : Vertically opposite angles

Check:-

$\sf= > 3x + 2 = 62$

$\sf= > 3x = 60$

$\sf= > x = \dfrac{60}{3} = 20$

$\sf = > 3x + 2 = 3 \times 20 + 2 = 62^{\circ}$