find the value of x in the following
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anglePQR = 180°-60°=120°. (linear pair)
angleQPT = 180°-70°=110°. (linear pair)
anglePTS = angleQRS = x
the sum of all angles of a pentagon = 540°
anglePQR+angleQRS+
angleRST+angleSTP+angleTPQ = 540°
=> 120°+x+30°+x+110°=540°
=> x+x+120°+30°+110°=540°
=> 2x+260°=540°
=> 2x = 540°-260°
=> x = 280/2
=> x = 140°
angleQRS = angleSTP = 140°
I hope this answer helps you.
hemee28:
thank you for answering my question
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