Math, asked by singhsajita142, 2 months ago

find the value of x in the following 6^0÷6^-1=6^x​

Answers

Answered by pravalikakolipaka1
0

6^0=1

6^-1=1/6

1÷1/6=6

x=1

Answered by paridhimalhotra07
0

Answer:

 {6}^{0}  \div  {6}^{ - 1}  =  {6}^{x}  \\  1 \div  \frac{1}{6}  =  {6}^{x}  \\ 1 \times 6 =  {6}^{x}  \\  {6}^{1}  =  {6}^{x}  \\  \\ x = 1

there you go :)

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