find the value of X in the following
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In triangle ABC
45°+50°+2+35°+1=180° (sun of all internal angle on triangle)
80°+50°+1+2=180°
130°+1+2=180°
1+2=180°-130°
1+2=50° -----(i)
In triangle ADC
x+1+2=180°
From (i)
x+50°=180° (1+2=50°)
x=180°-50°
x=130°
45°+50°+2+35°+1=180° (sun of all internal angle on triangle)
80°+50°+1+2=180°
130°+1+2=180°
1+2=180°-130°
1+2=50° -----(i)
In triangle ADC
x+1+2=180°
From (i)
x+50°=180° (1+2=50°)
x=180°-50°
x=130°
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