FIND THE VALUE OF X IN THE FOLLOWING FIGURE
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1. angle BAD = 60⁰
angle ADC= 60⁰ (alternative interior angles)
In ∆EDC,
angleE + angleD + angleC =180⁰
x + 60⁰ + 45⁰ = 180⁰
x + 105⁰=180⁰
x= 75⁰
2. On rt.∆ ABC,
angleA + angleB + angleC =180⁰
40⁰+90⁰+ angleB =180⁰
angleB= 180—130= 50⁰
In ∆EBD
angleE - angleB + angle D=180⁰
100⁰+50⁰+ angleD=180⁰
angleB=180—150= 30⁰=x
Hope it cleared your doubt.
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