Question

Find the value of x in the following figure​

Answer 1

Answer:

The value of $y$ is $65^{0}$.

Step-by-step explanation:

Given : O is the center.

           Four rays coming from the center.

           The angles made by the rays are $50^{0} ,40^{0} ,130^{0}$ and $(2y+10^{0})$.

To find : The value of y.

Solution :

• It is given that O is the center.

           Four rays coming from the center.

           The angles made by the rays are $50^{0} ,40^{0} ,130^{0}$ and $(2y+10)^{0}$.

• As we know that, measure of circle is $360^{0}$.
• In order to find the value of $y$, we have to use the above property of circle.

       $50^{0} +40^{0} +130^{0} +(2y+10)^{0} = 360^{0}$  

•    On solving, we get

                     ∴ $220^{0}+(2y+10)^{0} =360^{0}$

                             ∴ $(2y+10)^{0}=360^{0}-220^{0}$

                                       ∴ $2y=140^{0} -10^{0}$

                                        ∴ $2y=130^{0}$

                                        ∴ $y=(\frac{130}{2} )^{0}$

                                        ∴ $y=65^{0}$

• ∴ The value of $y$ is $65^{0}$.