Find the value of x in the following figure, if AB || CD and BC || DE
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From the given figure we know that AB and CD are parallel line and BC is a transversal We know that ∠BCD and ∠ABC are alternate angles So we can write it as ∠BCD + ∠ABC = xo We also know that BC || ED and CD is a transversal From the figure we know that ∠BCD and ∠EDC form a linear pair of angles So it can be written as ∠BCD + ∠EDC = 180o By substituting the values we get ∠BCD + 75o = 180o On further calculation we get ∠BCD = 180o – 75o By subtraction ∠BCD = 105o From the figure we know that ∠BCD and ∠ABC are vertically opposite angles So we get ∠BCD = ∠ABC = x = 105o
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