Math, asked by manpartapsingh2008, 2 months ago

Find the value of x in the following pair
if2^9x-3 = (64)^x​

Answers

Answered by anishabakare
2

Answer:

x=1

Step-by-step explanation:

2^9^x^-^3 = 64^x

2^9^x^-^3  = 2^6^x

see base common

hence writing only the exponents

9x-3=6x

9x-6x=3

3x=3

x=3/3

x=1

Hope it helps you

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