Question

find the value of x in the given equation​

Answer 1

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Answer 2

• The value of x in the given equation is equal to 2.

Given :-

• [2^(3x - 1) + 10] ÷ 7 = 6

To Find :-

• Value of x ?

Formula used :-

• when a^m = a^n => m = n { where a ≠ 0, 1 }

Solution :-

→ [2^(3x - 1) + 10] ÷ 7 = 6

taking 7 into LHS side and changing divide sign into multiply,

→ 2^(3x - 1) + 10 = 7 × 6

→ 2^(3x - 1) + 10 = 42

taking 7 into LHS side and changing add sign into subtraction,

→ 2^(3x - 1) = 42 - 10

→ 2^(3x - 1) = 32

writing RHS part as factors of prime,

→ 2^(3x - 1) = 2 × 2 × 2 × 2 × 2

→ 2^(3x - 1) = 2⁵

using a^m = a^n => m = n we get,

→ 3x - 1 = 5

→ 3x = 5 + 1

→ 3x = 6

dividing both sides by 3,

→ x = 2 (Ans.)

Hence, the value of x in the given equation is equal to 2.

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