Question

find the value of x in the given equation [3x-4]=5​

Answer 1

Answer:

I hope

Step-by-step explanation:

3x-4=5

3x=5+4

3x=9

x=9/3

x=3

Answer 2

Answer:

Step-by-step explanation:

First, move one of the two square roots from left to right hand side:

sqrt(3*x+4)=3+sqrt(x-3)

and square both sides (bearing in mind that this may result in adding solutions which do not belong):

3*x+4=(3-sqrt(x-3))^2=9–6*sqrt(x-3)+(x-3)=(x+6)-6*sqrt(x-3).

Next, move (x+6) from right to left hand side

(3*x+4)-(x+6)=2*x+2=-6*sqrt(x-3) ===> x-1=-3*sqrt(x-3).

Once again square both sides (which again might add solutions):

(x-1)^2=x^2–2*x+1=9*(x-3)=9*x-27 ===> x^2–11*x+28=0.

Notice now that 4+7=11 and 4*7=28 and therefore the roots of the last quadratic equation are exactly