find the value of x in the given figure
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Answer:
72°
because T =90
P=30
90+30=120
another angle i.e congruent to x is 60 as (180-120 =60 )
x is congruent to it so it is also 60
48 +60=108
180-108=72
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in figure, it is clearly shown that, QT is perpendicular on PR,
so, angle PTQ = 90°
let PS and QT intersect at A
from ∆PAT,
angle PAT + angle APT + angle PTA = 180°
⇒angle PAT + 30° + 90° = 180°
⇒angle PAT = 180° - 120° = 60°
it is clear that, angle PAT = angle QAS
from ∆QAS,
angle SQA + angle QAS + angle ASQ = 180°
⇒48° + 60° + x = 180°
⇒108° + x = 180°
⇒x = 180° - 108° = 72°
hence, x = 72°
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