Find the value of x in the given figure.
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⠀⠀ıllıllı uoᴉʇnloS ıllıllı
In the cyclic quadrilateral ABCD
∠ABC = 180° - 120° = 60°
∠BCA = 90°
Therefore:
x = ∠BAC = 180°- (90° + 60°) = 30°
- Hence, the value of x is 30°.
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3
Answer:
In trapezium ABCD
D=B
so,B=120°
and also A=C
so,(120°+120°+A°+C°)=360°
240+2A=360
2A=360-240=120°
A=120/2=60°
therefore,x=60/2=30°
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