find the value. of x in the given figure
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1
Answer:
70°
Step-by-step explanation:
angle SQR + angle PQR =180°. ... angles in linear pair
therefore, angle PQR=50°
angle PQR +X+anglePRQ=180°
50+x+60=180
110+x=180
X=180-110
x=70°
also we can solve this question by remote interior angle theorem
angle SQR = angleQPR + Angle PRQ
130=x+60
x=130-60
x=70°
Answered by
0
in given ∆ PQR
Angle PRQ is 60°
Angle SQR is 130°
therefore : angle SQR +angle PQR =180° ( angle sum property of a triangle)
=130°+angle PQR = 180°
= angle PQR = 180° -130°
= angle PQR = 50°
therefore,
angle PQR + angle QRS + angle QPR (x) =180° (angle sum property)
= 50°+60°+ x =180°
=110°+ x = 180°
x = 180°-110°
x = 70°
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