Math, asked by NandaniRaghuwanshi, 5 months ago

find the value. of x in the given figure​

Attachments:

Answers

Answered by payal8parkhe
1

Answer:

70°

Step-by-step explanation:

angle SQR + angle PQR =180°. ... angles in linear pair

therefore, angle PQR=50°

angle PQR +X+anglePRQ=180°

50+x+60=180

110+x=180

X=180-110

x=70°

also we can solve this question by remote interior angle theorem

angle SQR = angleQPR + Angle PRQ

130=x+60

x=130-60

x=70°

Answered by Anonymous
0

in given ∆ PQR

Angle PRQ is 60°

Angle SQR is 130°

therefore : angle SQR +angle PQR =180° ( angle sum property of a triangle)

=130°+angle PQR = 180°

= angle PQR = 180° -130°

= angle PQR = 50°

therefore,

angle PQR + angle QRS + angle QPR (x) =180° (angle sum property)

= 50°+60°+ x =180°

=110°+ x = 180°

x = 180°-110°

x = 70°

Similar questions