Question

Find the value of X in the given figure​

Answer 1

Answer:

x=2

Step-by-step explanation:

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Answer 2

Answer:

$x = \sqrt{ \sqrt{2} + 1 }$

Step-by-step explanation:

$in \: \: triangle \: \: abc \\ using \: \: pythagoras \: \: theorem \\ {(hy)}^{2} = {(b)}^{2} + {(s)}^{2} \\ = {1}^{2} + {1}^{2} \\ {(ca)}^{2} = 2 \\ca = \sqrt{2} \: \: \: \: unit \\ in \: \: triangle \: \: acd \\ using \: \: pythagoras \: \: theorem \\ {x}^{2} = \sqrt{2} + 1 \\ x = \sqrt{ \sqrt{2} + 1 }$

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