Find the value of ‘x’ in the given figure
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In ∆ABC
angle A+ angle B + angle C =180°
40° + 80° + angle BCA= 180°
angle BCA= 60°
by linear pair,
angle BCA + angle ACD=180°
60°+ angle ACD=180°
angle ACD= 120°
By exterior angle property
x=ACD +Angle D
x=120° + 50°
x=170°
hope it helps you :)
angle A+ angle B + angle C =180°
40° + 80° + angle BCA= 180°
angle BCA= 60°
by linear pair,
angle BCA + angle ACD=180°
60°+ angle ACD=180°
angle ACD= 120°
By exterior angle property
x=ACD +Angle D
x=120° + 50°
x=170°
hope it helps you :)
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