Find the value of x in the given figures.
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let meeting point of both altitudes be O then angle POA=QOC due to vertically opposite angles
and also angle P=angle Q=90° then both triangle similar by AA test.
so in similar triangles angles are congruent and by congruence of similar triangle we can say that angle PAO=angle QCP =35°
in second figure angle A is 90° then ANGLE FAC=90-50=40°
then in triangle ADC all angles sum is 180° then angle c =180-90-40=180-130=50°
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