find the value of'x' in the polynomial
2 a² +2xa+5a+10. If (a+x) is one of its
factores.
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Given f(x)=2x 2 +2ax+5x+10g(x)=x+ax+a=0x=−af(−a)=2(−a) 2 +2a(−a)+5(−a)+10⇒+2a 2 −2a 2 −5a+10=0⇒5a=10⇒a= 510 ∴a=2
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