Question

Find the value of “x” in the polynomial 2a2 + 2xa + 5a + 10 if (a + x) is one of its factors.​

Answer 1

$\blue{\bold{\underline{\underline{Answer:-}}}}$

Say,$f(a) = 2a^2 + 2xa + 5a + 10$

Since,$(a + x) is\: a \:factor\: of\: 2a^2 + 2xa + 5a + 10, f(-x) = 0$

So,$f(-x) = 2x^2 – 2x^2 – 5x + 10 = 0$

Or, $-5x + 10 = 0$

Thus, $x = 2$

Answer 2

Answer:

The value of x=2

Step-by-step explanation:

Given - The polynomial 2a2 + 2xa + 5a + 10 if (a + x) is one of its factors.

Find- Value of x

Step by step explanation

Say,f(a) = 2a^2+2xa+5a+10

Since ,(a+x) is the factor of 2a^2+2xa+5a+10

f(—x) = 0

So, f(—x) = 2x^2–2x^2–5x+ 10= 0

–5x+10 =0

5x=10

x= 2

Final answer= x= 2

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