Question

Find the value of “x” in the polynomial 2a2 + 2xa + 5a + 10 if (a + x) is one of its factors.​

Answer 1

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Say,$f(a) = 2a^2 + 2xa + 5a + 10$

Since,$(a + x) is\: a \:factor\: of\: 2a^2 + 2xa + 5a + 10, f(-x) = 0$

So,$f(-x) = 2x^2 – 2x^2 – 5x + 10 = 0$

Or, $-5x + 10 = 0$

Thus, $x = 2$

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Answer 2

Step-by-step explanation:

The value of a is termed to be 2.

Solution:

Given that

2 x ^ { 2 } + 2 a x + 5 x + 102x

2

+2ax+5x+10

Divide the 2 x ^ { 2 } + 2 a x + 5 x + 102x

2

+2ax+5x+10 by x+ax+a

By using the division method, we get the remainder } { 10 - 5 a = 0 } \\\\ { 5 a = 10 } \\\\ { \therefore a = 2 } \end{array}\end{gathered}

10−5a=0

5a=10

∴a=2