Question

Find the value of “x” in the polynomial 2a2 + 2xa + 5a + 10 if (a + x) is one of its factors.

Answer 1

Answer:

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Let f(a) = 2a2 + 2xa + 5a + 10

Since, (a + x) is a factor of 2a2 + 2xa + 5a + 10, f(-x) = 0

So, f(-x) = 2x2 – 2x2 – 5x + 10 = 0

-5x + 10 = 0

5x = 10

x = 10/5

Therefore, x = 2

Answer 2

Answer:

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Let f(a) = 2a2 + 2xa + 5a + 10

Since, (a + x) is a factor of 2a2 + 2xa + 5a + 10, f(-x) = 0

So, f(-x) = 2x2 – 2x2 – 5x + 10 = 0

-5x + 10 = 0

5x = 10

x = 10/5

Therefore, x = 2

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