Question

Find the value of “x” in the polynomial 2a2 + 2xa + 5a + 10 if (a + x) is one of its factors.

Answer 1

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$\mathbb\green{2a²+2ax+5a+10. = 2a(a+x)+5(a+2) So, x= 2.}$

Answer 2

Answer:

solution:-

= 2a²+2xa+5a+10

=2a(a+x)+ 5(a+2)

=$so, \: x= 2$