Question

find the value of x in the quadratic equation (2x-4)^2=64​

Answer 1

Step-by-step explanation:

The solutions are x=−6,x=2. Explanation: (2x+4)2=64. Taking the square root of both terms: √(2x+4)2=√64. 2x+4=±8.

Answer 2

Values of x are 6 and -2.

Given:

• $( {2x - 4)}^{2} = 64$

To find:

• Find the value of x in the quadratic equation.

Solution:

Step 1:

Take square root both the sides.

$\sqrt{( {2x - 4)}^{2} } = \sqrt{64}$

or

$\red{(2x - 4) = \pm8}$

Step 2:

Take +ve value.

$2x - 4 = 8$

or

$2x = 8 + 4$

or

$2x = 12$

or

$\bf \green{x = 6}$

Step 3:

Take -ve value.

$2x - 4 = - 8$

or

$2x = - 8 + 4$

or

$2x = - 4$

or

$\bf \pink{x = - 2}$

Thus,

Values of x are 6 and -2.

Learn more:

1) the zeros of the following polynomial are 3xsquare 15x+12 options both are positive, both are negative, one positive and...

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2) (ii) If p{x) = 2x2 + 4x + 6 is a quadratic polynomial then what is the value of sum of zeroes?

a) 0

b) 1

c) - 2

d) 4

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