Question

find the value of x in the trapezium ABCD given below​

Answer 1

Answer:

(x-20)+(x+40) = 180° (adjacent angles)

or, x-20+x+40 = 180°

or, 2x+20 = 180°

or, x = $\frac {180-20}{2}$

or, x = 80°

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Answer 2

Answer:

80°

Step-by-step explanation:

(x-20°)+(x+40°)=180°. ( adjacent angles are supplementary)

x-20°+x+40°=180°

2x+20°=180°

2x=180°-20°

2x=160°

x=160°÷2

x=80°