Question

find the value of x in the trapezium abcd given below​

Answer 1

Step-by-step explanation:

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given : ABCD is trapezium where angle A is x- 20° and D is x+40°.

therefore , according to the properties of trapezium ,

\begin{gathered}= > ( x + 40) + (x - 20) = 180 \\ \\ = > x + 40 + x - 20 = 180 \\ \\ = > 2x + 20 = 180 \\ \\ = > 2x = 180 - 20 \\ \\ = > 2x = 160 \\ \\ = > x = \frac{160}{2} \\ \\ = > x = 80\end{gathered}