Find the value of x in the trapezium ABCD given below.
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Answered by
0
Answer:
The value of x in the given trapezium is "80 degrees"
Answered by
1
Answer:
Here ,
∠A =(x−20)
∘
,∠D =(x+40)
∘
ABCD is trapezium,
⇒AB ∣∣ CD, so A and D are supplementary , therefore-
(x−20)+(x+40)=180
∘
2x+20
∘
=180
∘
2x=(180−20)
∘
2x=160
∘
x=80
∘
Step-by-step explanation:
it easy question
hope it helps you....
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