Math, asked by aruna12345, 6 months ago

Find the value of x in the trapezium ABCD given below.

Attachments:

Answers

Answered by bharathideviD
0

Answer:

The value of x in the given trapezium is "80 degrees"

Answered by ds8076388
1

Answer:

Here ,

∠A =(x−20)

,∠D =(x+40)

ABCD is trapezium,

⇒AB ∣∣ CD, so A and D are supplementary , therefore-

(x−20)+(x+40)=180

2x+20

=180

2x=(180−20)

2x=160

x=80

Step-by-step explanation:

it easy question

hope it helps you....

Similar questions