Question

Find the value of x in these all diagrams

Answer 1

(180-50)/2=130/2=65
65+x=180
x=180-65=115

(180-30)/2=150/2=75
75+/_R=180
/_R=180-75=105
105+52+x=180 (L.P.)
157+x=180
x=180-157=23

Answer 2

1)∆ABC is eqilateral,
hence <ACB = <ABC = (180-50)/2 = 65
x = (180-65) = 115°

2)in∆PQR,
x+52+(30+30) = 180
or, x = 180-112 = 68°

3) in∆ ACD,
x-(27+27) -(27+27) = 180
or , x -54 - 54 =180
or, x=180-108 = 72°

I hope it helps you....