Question

find the value of x in this figure

Answer 1

/_ACB+/_ACD=180°............LP
/_ACB+110°=180°
/_ACB=70°

120+/_ABC=180°.................LP
/_ABC=60°

SO
x+60°+70°=180...............ASP
x=180-130
x=50°






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Answer 2

✌Hey dear.....✌


Here is your answer....


In the given figure...

Angle ABC+120=180 degree[Linear pair]

So angle ABC=180-120 degrees
angle ABC=60degree.


And....

Angle ACB+110=180 degrees.(Linear pair)
Angle ACB=70


NOW IN triangle ABC.

=>60+70+X=180

=>130+X=180

=>X=50 degrees.


✌Hope it helps....✌