Question

find the value of x in which (5x+4),(4x-5)and(2x-2) are in AP​

Answer 1

Step-by-step explanation:

As (5x+4),(4x-5) and (2x-2) are in A.P.

So,there differences are same.

Now,4x-5-5x-4=D1

and,2x-2-4x+5=D2

As, differences are same, we get

4x-5-5x-4=2x-2-4x+5

-x-9 = -2x+3

-x+2x = 3+9

x = 12