Question

find the value of x in x^2√(x-1)(x-3) =0

Answer 1

Answer:

(x+1)/(x-3)<0 ?

Is ? --> roots are -1 and 3, so 3 ranges: , and --> check extreme value: if some very large number then --> in the 3rd range expression is positive, then in 2nd it'll be negative and in 1st it'll be positive again: + - +. So, the range when the expression is negative is: .

Thus the question basically becomes: is ?

(1) -1 < x < 1. Sufficient.

(2) x^2-4 < 0 --> . Not sufficient.

Answer: A.

Step-by-step explanation:

i hope this answers is useful for you bro

Answer 2

Heya Here's the required Answer mate

Answer:

(x+1)/(x-3)<0 ?

Is ? --> roots are -1 and 3, so 3 ranges: , and --> check extreme value: if some very large number then --> in the 3rd range expression is positive, then in 2nd it'll be negative and in 1st it'll be positive again: + - +. So, the range when the expression is negative is: .

Thus the question basically becomes: is ?

(1) -1 < x < 1. Sufficient.

(2) x^2-4 < 0 --> . Not sufficient

hope it helps