Question

Find the value of x:
int p=5;
int x= ++p * p++ - p;

Answer 1

Answer:

29

Explanation:

The operator precedence in Java is as follows:

1. postfix: expr++ expr--
2. unary: ++expr --expr -expr
3. multiplicative: *
4. additive: + -

The given expression will be evaluated in the following order:

p++: increment p by 1 = 6

++p: increment p by 1 = 6

After these two increment operations p becomes 7

(6) * (6) -  7

36 - 7

29