find the value of x+la+b)x+ ab
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Answer:
(a)103×104=(100+3)×(100+4)
=100
2
+(3+4)×100+3×4
=10000+700+12=10,712
(b)103×98=(100+3)×(100−2)
=100
2
+(3−2)×100+3×−2
=10,000+100−6=10,094
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