Question

Find the value of x of (3/4)^3(4/3)^-7=(3/4)^2x

Answer 1

Hey dear!


Here is yr answer.........


(3/4)^³ × (4/3)^-7 = (3/4)^2x


[ a^-1 = 1/a^1 ]


(3/4)^3 × (3/4)^7 = (3/4)^2x


[a^m × a^n = a^m+n]


(3/4)^3+7 = (3/4)^2x

(3/4)^10 = (3/4)^2x


Here, bases are equal, so the powers must be equal!

10 = 2x

x = 10/2

x = 5


Hope it hlpz.....

Answer 2

(3/4)^3 (3/4)^7 = (3/4)^2x
(3/4)^10 = (3/4)^2x
Bases are equal so powers should be equal.
2x=10
x = 5