find the value of x of an arithmetic progression2,x,26
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x=14
Step-by-step explanation:
Ap=2,x,26
First term,a=2
Second term,a2=x
third term,a3=26
Common difference,d=a2-a
also, d=a3-a2
therefore a3-a2=a2-a
26-x=x-2
26+2=x+x
2x=28
x=14
Hence, value of x is 14
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