find the value of x of equation 2x²+3x−6=0 by using quadratic equation
Answers
Step-by-step explanation:
The first term is, 2x2 its coefficient is 2 .
The middle term is, -3x its coefficient is -3 .
The last term, "the constant", is -6
Step-1 : Multiply the coefficient of the first term by the constant 2 • -6 = -12
Step-2 : Find two factors of -12 whose sum equals the coefficient of the middle term, which is -3 .
-12 + 1 = -11
-6 + 2 = -4
-4 + 3 = -1
-3 + 4 = 1
-2 + 6 = 4
-1 + 12 = 11
Observation : No two such factors can be found !!
Conclusion : Trinomial can not of the vertex is given by -B/(2A) . In our case the x coordina
The given question is we have to find the value of x of equation 2x²+3x−6=0 by using the quadratic equation.
The equation mentioned here is
The value of x is nothing but the roots of the quadratic equation.
The roots can be obtained by two methods they are tree factorisation and the formula method.
The real roots for the given equation are not obtained by the factorization method, therefore we are using a formula method.
The formula to find the roots of the quadratic equation is
The values a, b and c are the coefficient of the terms in an equation.
a = 2
b = 3
c = -6
substituting the values in the above formula we get.
In further proceedings, we get the values as
Therefore, the value of x is -4.885 and 1.135
The positive x value is 1.135
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