Find the value of (x-p)3 +(x-q)3+(x-r)3_ 3(x-p),(x-q)(x-r)if p+q+r=3x
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Answer:(x-p)^3+(x-q)^3-(x-r)^3-3(x-p)(x-q)(x-r)
=(X-p+x-q+x-r)^3=
3x-3x=0
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