Question

Find the value of X
please​

Answer 1

Step-by-step explanation:$sum \: of \: angles \: on \: straight \: line = 180$<EAD+<DAB=180°

<EAD=98°

98°+<DAB=180

<DAB=180-98=82°

<B=<BAC(angles opposite to the equal sides)

<ACD=<ADC{angles opposite to the equal sides}

let's take <<B=<BAC=x

<ACD=<ADC=y

<ABC+<DAB+<ADC=180°{sum of the angles of triangle is equal to 180 degrees}

substitute <<DAB=82°

x+y+82=180

x+y=180-82=98°

x+y=98°--------equation(1)

<ABC+<CAB=<ACD

x+x=y(sum of the two opposite angles of the triangle is equal to one external angle of the triangle)

2x=y------------Equation(2)

x=y/2----------equation(3)

substitute equation 3 in equation 1

x=y/2

x+y=98°

y/2+y=98°

(y+2y)/2=98°

3y=98×2

y=196/3

substituting y value in equation 1

x+y=98°

x+196/3=98

x=98-196/3=98/3°

in∆ ABC

<ABC=<BAC=x=98/3°

this is your answer,

I hope this will help you.

Answer 2

Hope it helps you

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