Question

find the value of x. please help me ​

Answer 1

in question-2 triangle PQR is a isoceles triangle.so angel Q = angleR =50

by angle sum property

180-50+50=80

X=80

Answer 2

Solution:-

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$\small\fbox{Figure\:1}$

Given that,

∠PRQ is 50°

and

∠QPR is x°

Now,

Let us assume ∠PQR as x°

According to the angle sum property,

$\small\fbox{Sum\:of\:all\:angles\:in\:a\:traingle\:is\:180°}$

So from this we get as :-

⟼x+x+50=180

⟼2x=180-50

⟼2x=130

⟼x=130/2

⟼x=65°

• Hence, the value of x is 65°

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$\small\fbox{Figure\:2}$

Given that,

∠MON =2x°

∠NMO = x°

And

∠MNO is 90°

According to the angle sum property,

$\small\fbox{Sum\:of\:all\:angles\:in\:a\:traingle\:is\:180°}$

So from this we get as,

⟼2x+x+90=180

⟼3x=180-90

⟼3x=90

⟼x=90/3

⟼x=30°

• Hence, the value of x is 30°
• 2x=2(30)=60°
• The angles in this triangle are 30°,60°,and 90°

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