find the value of x( please say fast)
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Answer:
in triangle adc, angle a=angle d=62°
in triangle abd, angle d=180°-62°=118°
and angle b =angle a
a=62°/2 =31°
so, x=93°
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1
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Pls mark as the brainliest
Step-by-step explanation:
∠CAD = ∠CDA (ΔCAD is isosceles )
∴ ∠CAD = ∠CDA = 1/2( 180 - 56 ) = 62°
∠ADB = 180 - 62
= 118
∠DAB = ∠DBA = 1/2 ( 180 - 118)
= 31°
x = ∠DAB + ∠CAD = 31 + 62 = 93
x = 93
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