Math, asked by dollyjain92, 14 hours ago

Find the value of x? please tell me ​

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Answers

Answered by STATUZ
1

Let The Other Three Sides Be x

Let The Other Three Sides Be xIn Trapezium ABCD

Let The Other Three Sides Be xIn Trapezium ABCDAngle B & C = 50°

Let The Other Three Sides Be xIn Trapezium ABCDAngle B & C = 50°By Angel Sum Property

Let The Other Three Sides Be xIn Trapezium ABCDAngle B & C = 50°By Angel Sum Property x+x+50°+50°=360°

Let The Other Three Sides Be xIn Trapezium ABCDAngle B & C = 50°By Angel Sum Property x+x+50°+50°=360°2x+100°=360°

Let The Other Three Sides Be xIn Trapezium ABCDAngle B & C = 50°By Angel Sum Property x+x+50°+50°=360°2x+100°=360°x=260/2

Let The Other Three Sides Be xIn Trapezium ABCDAngle B & C = 50°By Angel Sum Property x+x+50°+50°=360°2x+100°=360°x=260/2x=130°

Answered by k77303746
0

Answer:

total angle sum =360

add the given first two angles

  1. 50 +50=100
  2. 360-100=260
  3. 260/2=130
  4. so' x =130
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