Question

find the value of x pls
$\sqrt{5 \sqrt[3]{5} } \sqrt{5 \sqrt[3]{5} } \sqrt{5} = {25}^{x}$
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Answer 1

Answer:

$\sqrt{ \sqrt{5} \sqrt[3]{5} } \sqrt{ \sqrt{5} \sqrt[3]{5} } \sqrt{5} \\ = (\sqrt{ {5}^{ \frac{1}{2} }{{5}^{ \frac{1}{3} } } } ) {}^{2} \sqrt{5} \\ = {5}^{ \frac{1}{2} + \frac{1}{6} } \times {5}^{ \frac{1}{2} } \\ = {5}^{ \frac{1}{2} + \frac{1}{6} + \frac{1}{2} } \\ = {5}^{ \frac{7}{6} }$