Question

find the value of x
plz ​

Answer 1

Answer:

Q2- value of x = 5

Q3- value of x = 80

Answer 2

Answer:

Question-1

SOLUTION:

BC = base = 3

AC = Adjacent side = 4

Find: Hypothenuse= AB

We know

Hypotenuse^2 = base ^2 + A.side^2

Ab^2 = 3^2 + 4^2

Ab^2 = 9+16

Ab = √25

AB = 5

Answer: 5

QUESTION: 2

solution:

(Theorem: Outer angle of a triangle

= sum of two opposite angle)

From theorem

X + 30 = 110°

X = 110°-30°

X = 80°

Answer: 80°