Question

Find the value of x .

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Answer 1

Step-by-step explanation:

$\huge\underline{\underline{\ question}}$

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$7 \times {10}^{8} = \frac{3 {x}^{2} }{(0.6 - x)(0.2 - x)}$

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$\huge\underline{\underline{\ answer}}$

$7 \times {10}^{8} = \frac{3 {x}^{2} }{(0.6 - x)(0.2 - x)} \\ 7 \times {10}^{8} = \frac{3 {x}^{2} }{0.12 - 0.8x + {x}^{2} } \\ 7 \times {10}^{8} = \frac{30 {x}^{2} }{12 - 8x + 10 {x}^{2} } \\ 7 \times {10}^{8} = \frac{15 {x}^{2} }{6 - 4x + 5 {x}^{2} } \\ 42 \times {10}^{8} - 28 \times {10}^{8} x + 35 \times {10}^{8} {x}^{2} = 15 {x}^{2} \\ {10}^{8} (42 - 28x + 35 {x}^{2} ) = 3 {x}^{2} \\ 42 - 2 8{x}^{} = \frac{3 {x}^{2} }{ {10}^{8} } - 35 {x}^{2} \\ 42 - 28x = \frac{3 {x}^{2} - 35 {x}^{2} \times {10}^{8} }{ {10}^{8} } \\( 42 - 28x ) \times {10}^{8} = (3500000000 - 3) {x}^{2} \\ (42 - 28x) \times {10}^{8} = 3499999997 {x}^{2} \\( 34 {x}^{2} - 28x+ 42) \times {10}^{8} = 0 \\ (17 {x}^{2} - 14x + 21) = 0 \\ x = \frac{14 + \: or \: - \sqrt{ - 1232} }{2(17)} \\ roots \: are \: not \: real..$