Math, asked by Alkasha14, 10 months ago

find the value of x
plzz give pic as solution if possible​

Attachments:

Answers

Answered by Anonymous
2

Answer:

 \boxed{\huge{\sf x = 2}}

Step-by-step explanation:

 \sf  Solve  \: for \:  x \:  over \:  the  \: integers: \\ \sf  \implies  {3}^{2x + 1} \div 9 = 27 \\  \\  \sf  \implies  \frac{ {3}^{2x + 1} }{9}  = 27 \\  \\ \sf 9 =  {3}^{2}  :  \\ \sf  \implies  \frac{ {3}^{2x + 1} }{ {3}^{2} }  = 27 \\  \\ \sf  \implies  {3}^{(2x + 1) - 2}  = 27 \\  \\ \sf  \implies  {3}^{2x + 1 - 2}  = 27 \\  \\ \sf  \implies  {3}^{2x - 1}  = 27 \\  \\  \sf 27 =  {3}^{3}  :  \\ \sf  \implies  {3}^{2x - 1}  =  {3}^{3}  \\  \\ \sf Equate \:  exponents  \: of \:  3 \:  on  \: both \:  sides: \\ \sf  \implies 2x - 1 = 3 \\  \\ \sf  \implies 2x = 3 + 1 \\  \\ \sf  \implies 2x = 4 \\  \\ \sf  \implies x =  \frac{4}{2}  \\  \\ \sf  \implies x = 2

Similar questions