Question

find the value of x power 4 +1 upon x power 4 if x-1 upon x=3​

Answer 1

Answer:

x power 4 +1 upon x power 4

$= {x}^{4} + \frac{1}{ {x}^{4} }$

$\frac{x - 1}{x} = 3 \\ x - 1 = 3x \\ 2x = - 1 \\ x = - \frac{1}{2}$

So,

$= {x}^{4} + \frac{1}{ {x}^{4} } \\ = { (- \frac{1}{2} })^{4} + {( - 2)}^{4} \\ = \frac{1}{16} + 16 \\ = 16 \frac{1}{16} = \frac{257}{16}$